Question 897678
{{{n(n+1)=-8+n^2}}}


{{{n^2-n(n+1)-8=0}}}
{{{n^2+n=-8+n^2}}}
{{{n=-8}}}


The integers are -8 and -7.


Recheck in equation:
(-8)(-7)=-8+(-8)^2
56=-8+64
56=64-8=56 yes.