Question 10292
{{{sqrt( -7 )(sqrt( -4 ) - sqrt( 8 ))}}}


First let's change the square roots of negatives to "i" notation:
{{{i*sqrt(7) *(2*i - sqrt(8))}}}
{{{i *sqrt(7)* 2*i - i *sqrt(7) * sqrt(8) }}}
{{{2*i^2* sqrt(7) - i* sqrt(7) *sqrt(4) *sqrt(2) }}}


Remember that {{{i^2 = -1}}}
{{{-2 *sqrt(7) - 2i* sqrt (14) }}}


R^2 at SCC