Question 897132
Please help me. I have no clue on what numbers to use for this parabola since my Y intercepts come out as big numbers.
I need to sketch the parabola with the equation 4x^2-16x+15 and label the vertex, axis of symmetry, x and y intercepts. Should I divide by 4?
<pre>
Standard form of a parabolic equation: {{{y = ax^2 + bx + c}}}
The x-coordinate of the vertex occurs at: {{{x = - b/a}}}. This is also the axis of symmetry.
The y-coordinate of the vertex occurs at: {{{f(x) = 4x^2 - 16x + 15}}}, where x is the value of the x-coordinate of the vertex
The x intercepts, or roots occur at the solutions to: {{{4x^2 - 16x + 15 = 0}}}
The y-intercept occurs at {{{f(0) = 4x^2 - 16x + 15}}}. Looking at the equation, it should be: {{{15}}}

**FYI
If you intend to create the vertex form of the equation, then you'd need to divide through by 4.
Otherwise, that's too much work.