Question 897045
2x^2 = 7x-3
2x^2 -7x +3 = 0
the quadratic formula is x = (-b +or- square root (b^2 -4ac))/ 2a and standard form for quadratic is ax^2 +bx +c = 0
now we can solve our equation
x = (7 + square root(7^2 -4*2*3))/(2*2) =  8.25
x = (7 - square root(7^2 -4*2*3))/(2*2) =  5.75
therefore x = 8.25 or 5.75