Question 897028
-4 - 8 - 8a <= -76  or  -4 - 8 - 8a >= 76
-12 +8a <= -76  or -12 +8a >= 76
8a <= -64  or  8a >= 88
a <= -8  or a >= 11
Therefore the solution to -4 - | 8 - 8a| >= 76 consists of two intervals
a <= -8 and a >= 11