Question 896944
in a two digit number the sum of the digits is 13, if the number is subtracted from the one obtained by reversing the digits the result is 45. find the number
***
let u=units digit
let t=tens digit
..
t+u=13
t=13-u
..
10u+t-(10t+u)=45
10u+t-10t-u=45
10u+13-u-10(13-u)-u=45
10u+13-u-130+10u-u=45
18u=162
u=9
t=13-u=4
number=49