Question 896968

Solve 5^(x^2+x) = 1
<pre>
{{{a^b = 1}}}, when b = 0
Thus, for {{{highlight(highlight(5^(x^2 + x) = 1))}}}, {{{5^o = 1}}}, and so: {{{x^2 + x = 0}}}______x(x + 1) = 0
Therefore, {{{highlight_green(x = 0)}}}, or {{{highlight_green(x = - 1)}}}
You can do the check!! 

Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously. 

For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra, 
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.