Question 896968
{{{5^(x^2+x) = 1}}}

Take log to the base 5.

Then you can take (x^2+x) infront

{{{(x^2+x)*log5 = log1}}}

{{{x^2 +x= 0}}}

{{{x(x+1)=0}}}

{{{x=0}}} or {{{x= -1}}}