Question 896823
Geometric sequence is defined as
Xn = ar^(n-1)
in our case a = 6 and r = 1/2 and the geometric sequence looks like
6, 3, 3/2, 3/4, .....
the sum of a geometric sequence to infinity is defined as
a(1-r^n / 1-r)
note as n goes to infinity (1/2)^n approaches 0, then we have
6*(1/ 1/2) = 6*2 = 12