Question 896832
How do I solve for "x" in "-3x^2+2=29"?
I know the first thing is to subtract "29" from both sides, so:
"-3x^2+27=0"
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-3x^2+2=29
Or, subtract 2
-3x^2 = 27
Divide by -3
x^2 = -9
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{{{x = +3i}}}
{{{x = -3i}}}
{{{i = sqrt(-1)}}}