Question 896644

The length of a rectangle is five times its width. If the area of the rectangle is 500in^2, find its perimeter 
<pre>
Let width be W
Then length is: 5W
Thus, W(5W) = 500
{{{5W^2 = 500}}}
{{{W^2 = 500/5}}}
{{{W^2 = 100}}}
W, or width = {{{sqrt(100)}}}, or {{{10}}}
Length: 5(10), or 50
Perimeter: 2(L + W), or 2(10 + 50), or 2(60), or {{{highlight_green(120)}}} inches