Question 896643

The length of a rectangle is 5 cm longer than its width. If the perimeter of the rectangle is 46 cm, find its area.
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Let width be W
Then length = W + 5
Since perimeter = 46, then: 2W + 2(W + 5) = 46
2W + 2W + 10 = 46
4W + 10 = 46
4W = 46 – 10
4W = 36
W, or width = {{{36/4}}}, or 9
Length: 9 + 5, or 14
Area: 9(14), or {{{highlight_green(126)}}} sq cm