Question 896380
Q:
According to a candy company, packages of a certain candy contain 17% orange candies. Find the approximate probability that the random sample of 300 candies will contain 20% or more orange candies. Using a normal approximation, what is the probability that at least 20% of 300 randomly sampled candies will be orange?
A:
Let X = number of candies that are orange in a sample of 300 candies.
The mean of X is 0.17(300) = 51
The variance of X is 0.17(1-0.17)(300) = 42.33
using normal distribution and applying the correction for continuity, the approximate probability is
P(X ≥ 59.5) = P(Z ≥ {{{(59.5 - 51)/sqrt(42.33)}}})
            = P(Z ≥ 1.3065)
            = {{{highlight(0.0957)}}}