Question 896368
Natalie has some nickels, Dirk has some dimes and Quincy has some quarters.
 Dirk has five more dimes than Quincy has quarters.
d = q + 5 
If Natalie gives Dirk a nickel, Dirk gives Quincy a dime, and Quincy gives Natalie a quarter; they will all have the same amount of money.
.10d + .05 - .10 = .25q +.10 - .25
.10d -.05 = .25q - .15
.10d = .25q -.15 + .05
.10d = .25q - .10
multiply by 10 
d = 2.5q - 1
we know that d = q + 5
q + 5 = 2.5q - 1
5 + 1 = 2.5q - q
6 = 1.5q
q = 6/1.5
q = 4 quarters
then
d = 4 + 5 = 9 dimes
:
Find n:
.05n -.05 + .25 = .05n + .20
we know that
.05n + .20 = .25q -.15
Replace q with 4
.05n + .20 = 1.0 - .15
.05n = .85 - .20
.05n = .65
n = .65/.05
n = 13 nickels 




 How many coins did each have originally?