Question 896368
Dirk has (x+5).10
Quincy has x(.25)
Natalie has (y-1).05
Dirk has .05 + (x+5).10
Dirk has .05 + (x+4).10
Quincy has x(.25) +.10
Quincy has (x-1).25 +.10
Natalie has (y-1).05 +.25
now we can write the final equations 
Dirk = Natalie = Quincy
.05 + (x+4).10 = (y-1).05 +.25 = (x-1).25 +.10
.05 +.10x +.40 = .05y -.05 +.25 = .25x -.25 +.10
.10x +.45 = .05y +.20 = .25x -.15
first solve for x
.10x +.45 = .25x - .15
-.15x = -.60
x = 4
now we can solve for y
.05 + (4+4).10 = (y-1).05 +.25
.85 = .05y -.05 + .25
.85 = .05y +.20
.05y = .65
y = 13
Dirk had 9 dimes, Quincy had 4 quarters and Natalie had 13 nickels