Question 896352
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=4 b=8 c=k
A)  sqrt( 8^2-4*4*k ))


solve for k
B) 0 =  sqrt( 8^2-4*4*k ) if d=0 there is one root (double root)
when k=4
C) 0< sqrt( 8^2-4*4*k ) if d is positive there are two real roots
when k<4
D) 0>  sqrt( 8^2-4*4*k )if d is negative then there are imaginary roots
when k>4

E)  k=1 k=2 k=3 

*[invoke change_this_name4450 4, 8, 4, "x"]
*[invoke change_this_name4450 4, 8, 3, "x"]
*[invoke quadratic_formula 4, 8, 2, "x"]
*[invoke quadratic_formula 4, 8, 1, "x"]