Question 896157
The center is the midpoint of those endpoints.

{{{x=(-2+5)/2=3/2}}}
and
{{{y=(4-5)/2=-1/2}}}

The center of the circle is (3/2,-1/2).


The value of the diameter is {{{sqrt((-2-5)^2+(4-(-5))^2)}}}
{{{sqrt(49+81)}}}
{{{sqrt(130)}}}, the diameter.
The RADIUS is (1/2)sqrt(130)
and the square of this is {{{130/4=32&1/2}}}.


CIRCLE:  {{{highlight((x-3/2)^2+(y+1/2)^2=32&1/2)}}}