Question 896224

Please help me solve this problem 6x/(x^2-4)+3/(2-x) I am trying to understand the steps and how to figure it out.
<pre>
This is not an equation so it CANNOT be solved. It can, however be SIMPLIFIED.
If it's the following expression: {{{6x/(x^2 - 4) + 3/(2 - x)}}}, then it can be simplified to:
{{{6x/(x^2 - 4) + 3/(2 - x)}}} 
{{{6x/((x - 2)(x + 2)) + 3/(2 - x)}}} ---------- Factoring denominator of 1st fraction
{{{6x/((x - 2)(x + 2)) + (- 1(3))/(-1(2 - x))}}} ----- Multiplying 2nd fraction by - 1
{{{6x/((x - 2)(x + 2)) + (- 3)/(- 2 + x)}}}
{{{6x/((x - 2)(x + 2)) - 3/(x - 2)}}}
{{{(6x - 3(x + 2))/((x - 2)(x + 2))}}} ----- Multiplying by LCD, (x - 2(x + 2)
{{{(6x - 3x - 6)/((x - 2)(x + 2))}}}
{{{(3x - 6)/((x - 2)(x + 2))}}}
{{{(3(x - 2))/((x - 2)(x + 2))}}}
{{{(3cross((x - 2)))/(cross((x - 2))(x + 2))}}}
{{{highlight_green(highlight_green(3/(x + 2)))}}}