Question 896221
We'll be using the formula {{{A = P*(1+r/n)^(n*t)}}} where

A = amount in the account after t years
P = initial deposit (principal)
r = interest rate as a decimal
n = compounding frequency
t = number of years


In this case,


A = unknown (we're solving for it)
P = 800
r = 0.06 (6% = 6/100 = 0.06)
n = 1 (compounded annually = compounding 1 time per year)
t = 2 years


Plug all this info into the formula to get...



{{{A = P*(1+r/n)^(n*t)}}}


{{{A = 800*(1+0.06/1)^(1*2)}}}


{{{A = 800*(1+0.06)^(1*2)}}}


{{{A = 800*(1.06)^(1*2)}}}


{{{A = 800*(1.06)^(2)}}}


{{{A = 800*(1.1236)}}}


{{{A = 898.88}}}



She will have <font color="red">$898.88</font> in the account at the end of the two years.



Side Note: She has earned A - P = 898.88 - 800 = $98.88 in interest alone.