Question 896112
Inverse Operations.  Using the equation <i>exactly</i> as shown in your request,


{{{Q=V(10X2+A)}}}


{{{Q/V=10X2+A}}}


{{{Q/V-A=10X2}}}


{{{(Q/V-A)/(10*2)=X}}}


{{{highlight(X=(Q/V-A)/20)}}}


or further simplification,
{{{Q/(20V)-A/20}}}

{{{Q/(20V)-AV/(20V)}}}

{{{highlight((Q-AV)/(20V))}}}