Question 896201
If we have cos ( theta + (pi/4)) = sqrt(2)/2 and the range is between 0 greater than/or equal to theta less than 2pi. What is theta? 
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{{{cos(theta+pi/4)=sqrt(2)/2}}}
{{{(theta+pi/4)=arccos(sqrt(2)/2)}}}
{{{(theta+pi/4)=pi/4}}}
{{{theta=0}}}
and
{{{(theta+pi/4)=7pi/4}}}
{{{theta=3pi/2}}}
{{{theta}}}=0, 3π/2