Question 895998
equation is (y+1)^2 = x+3


take the square root of both sides of this equation to get:


y+1 = plus or minus sqrt(x+3)


subtract 1 from both sides of this equation to get:


y = -1 plus or minus sqrt(x+3)


the upper half of the parabola is y = -1 plus sqrt(x+3)


the lower half of the parabola is y = -1 minus sqrt(x+3)


here's the graph of the upper half which is y = -1 + sqrt(x+3).


{{{graph(600,600,-10,10,-10,10,-1+sqrt(x+3))}}}


here's the graph of the lower half which is y = -1 - sqrt(x+3).


{{{graph(600,600,-10,10,-10,10,-1-sqrt(x+3))}}}


here's the graph of both halves which is y = -1 + sqrt(x+3) and the graph of y = -1 - sqrt(x+3).


{{{graph(600,600,-10,10,-10,10,-1+sqrt(x+3),-1-sqrt(x+3))}}}