Question 895844
A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width if the area of the pool and path combined is 416 square meters what is the width of the path
<pre>
Let UNIFORM width of path, be W
Then width on either end of pool = W + W, or 2W
Area of pool and path = (2W + 10)(2W + 20), and area of pool and path = 416.
Thus, (2W + 10)(2W + 20) = 416
{{{4W^2 + 60W + 200 = 416}}}
{{{4W^2 + 60W + 200 - 416 = 0}}}
{{{4W^2 + 60W - 216 = 0}}}
{{{4(W^2 + 15W - 54) = 4(0)}}}
{{{W^2 + 15W - 54 = 0}}}
(W - 3)(W + 18) = 0 
W, or width of path = {{{highlight_green(highlight_green(3))}}} m
You can do the check!! 

Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously. 

For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra, 
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.