Question 895586
{{{x^2+12x+y+41=0}}}
{{{x^2+12x+36+y+41=36}}}
{{{(x+6)^2+y+41=36}}}
{{{y=-(x+6)^2-5}}}
Parabola with vertex (-6,-5) opens downwards.
Focus 
{{{y+5=-(x+6)^2}}}
{{{-(y+5)=(x+6)^2}}}
{{{4p=-1}}}
{{{p=-1/4}}}
Focus : (-6,-5-1/4)=(-6,-21/4)
{{{graph(300,300,-10,2,-10,2,-(x+6)^2-5)}}}