Question 895720
<pre>
The other tutor thought the x on the second term was 
on the bottom.


{{{-1/2-expr(5/6)x}}}{{{""=""}}}{{{3/4}}}

It won't be hard if you clear of fractions first:

The LCD of the denominators 2,6, and 4 is 12.
So multiply every term by 12

{{{12(-1/2)-12(expr(5/6)x)}}}{{{""=""}}}{{{12(3/4)}}}

{{{-6-10x)}}}{{{""=""}}}{{{9}}}

{{{-10x)}}}{{{""=""}}}{{{15}}}

{{{x)}}}{{{""=""}}}{{{15/(-10)}}}

{{{x)}}}{{{""=""}}}{{{-3/2}}}

Edwin</pre>