Question 75592
distance going = distance coming back
(speed*time going) = (speed*time coming back)
{{{(s - 50)*5 = (s + 50)*4.09}}}
{{{5s - 250 = 4.09s + 204.5}}}
{{{.91s = 454.5}}}
{{{s = 499.45}}} mph answer
check
{{{(s - 50)*5 = (s + 50)*4.09}}}
{{{(499.45 - 50)*5 = (499.45 + 50)*4.09}}}
{{{449.45*5 = 549.45*4.09}}}
{{{2247.25 = 2247.25}}}
OK