Question 895641
 Fred begins walking toward John's house at 3 miles per hour.
 John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 miles per hour.
 How long will it be before they meet if the distance between the houses is 4 miles.
:
let t = the walking time of the two boys (in hrs)
:
When they meet, they will have traveled a total of 4 mi
Write a distance equation dist = speed * time
Fred's dist + John's dist = 4 mi
3t + 2t = 4
5t = 4
t = 4/5 hr or .8(60) =  48 min