Question 895625
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Let *[tex \Large x\ =\ m\angle B].  Then *[tex \Large 4x\ =\ m\angle A].  Since the sum of the measures of a linear pair is 180 degrees (by definition):


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 4x\ =\ 180]


Solve for *[tex \Large x] and then calculate *[tex \Large 4x], or calculate *[tex \Large 180\ -\ x] if you would rather.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \