Question 895493
<pre>
0! is defined as 1.

C(n,0) = {{{n!/(0!*(n-0)!)}}} = {{{n!/(1*n!)}}} = {{{cross(n!)/(1*cross(n!))}}} = 1

But the real proof is by common sense:

If you have n things, then the number of ways you can choose
to take 0 of them is 1 way, -- and that 1 way is to not take any!

Edwin</pre>