Question 75623
{{{F = (9C+160)/5}}}
{{{F = (9/5)C+32}}} reduce 160/5 to 32 
{{{F - 32 = (9/5)C+cross(32-32)}}} Subtract 32 from both sides
{{{(5/9)(F - 32) = cross((5/9)(9/5))C}}} Multiply both sides by 5/9. This cancels the 9/5 on the right side
{{{C=(5/9)(F - 32)}}} So this is what C equals