Question 895481
<pre>The formula is

{{{h=h[0]+v[0]t-16t^2}}}

h = final height in feet
h<sub>0</sub> = the initial height in feet
v<sub>0</sub> = the initial velocity in ft/sec
t = the final time.

h = what we are looking for.
h<sub>0</sub> = 64 ft
v<sub>0</sub> = 16 ft/sec
t = 1/4 sec

{{{h=h[0]+v[0]t-16t^2}}}
{{{h=64+16(1/4)-16(1/4)^2}}}
{{{h=64+4-16(1/16)}}}
{{{h=68-1}}}
{{{h=67}}}

Answer: 67 feet above the ground

[Notice: Since the balloon was going up when the
sandbag was released, the sandbag was still going up
1/4 of a second after it was released.  It had not
started to fall yet.] 

Edwin</pre>