Question 895476
The distance of the first car is 
{{{D[1]=15*t}}}
The distance of the second car is,
{{{D[2]=(1/2)(2)t^2}}}
Find {{{t}}}} when {{{D[1]=D[2]}}},
{{{15t=t^2}}}
{{{t^2-15t=0}}}
{{{t(t-15)=0}}}
Two solutions:
{{{t=0}}} <--- When they were both at the gas station.
and
{{{t-15=0}}}
{{{t=15}}{{{sec}}}