Question 75478
(x/3 + 3/4)(3x/4 – 3/5)
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FOIL it, here it is step-by-step
First: (x/3) * (3x/4) = 3x^2/12
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Outer: (x/3) * -(3/5) = -3x/15
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Inner: (3/4) * (3x/4) = 9x/16
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Last: (3/4) * -(3/5) = -9/20
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Put them altogether:
{{{(3x^2)/12 - (3x)/15 + (9x)/16 - 9/20}}}
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Combine the two center terms, the common denominator; 16*15 = 240
{{{(16)(3x/240) - (15)(9x)/240}}} = {{{(48x/240) - (135x)/240}}} = {{{-(87x)/240}}}; this is the solution middle term
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Note on the 1st term: {{{(3x^2)/12}}} = {{{x^2/4}}}; the 3 cancels into 12
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We end up with:
{{{x^2/4 - (87x)/240  - 9/20}}}
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