Question 895258

How do I solve these two logarithms.

I have the problems 

5 ^x-1/3 = power 3 square root of 5 (the 3 is small and on top of the square root)

and

log (base 4) (x-2) + log (base 4) (x+1) =1

I would like some help with the steps that I could go about solving these logs

thank you
<pre>
If {{{5^x - 1/3 = root (3, 5)}}}? Then {{{highlight_green(x = 0.443988)}}}

{{{log (4, (x - 2)) + log (4, (x + 1)) = 1}}}
{{{highlight_green(x = 3)}}}
OR
x = - 2 (ignore,as this is an EXTRANEOUS solution)
You can do the check!! 

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