Question 895256
{{{(x+3)^2=-8(y-5)}}}. 
How do I find P for this problem? I know that its from the translated form of the vertical axis of symmetry which is (x-h)^2=4p(y-k).
***
Given equation is that of a parabola which opens downward.
Its basic form of equation:
(x-h)^2=-4p(y-k), (h,k)=coordinates of vertex)(Don't forget the minus sign)
For given equation:(x+3)^2=-8(y-5)
4p=|-8|=8
p=2