Question 895216
we want m such that the factors a*b=m,a+b=8  and b-a=4
b+a=8
b-a=4
2b=12
b=6
a=2
m=6*2=12

(x-2)*(x-6)=x^2-8x+12


*[invoke change_this_name4450 1, -8, 12, "x"]

another way
x^2-8x+m=0
8/2=4
make the square
and set it equal to the difference 4
(x-4)^2=4
multiply it out
x^2-8x+16=4
x^2-8x+12=0
m=12