Question 895002
{{{y-x=4}}}
{{{3x+y=16}}}
From the first equation,
{{{y=x+4}}}
Substitute into the second equation,
{{{3x+(x+4)=16}}}
{{{4x+4=16}}}
{{{4x=12}}}
{{{x=3}}}
Then,
{{{y=3+4}}}
{{{y=7}}}