Question 894922
let 's say the man walks 1 hour
r*t=d
3*1=3 km
so he walks 3 km up
so he walks 3 km downhill twice as fast so he takes half the time

6*.5=3
1 hour up and 1/2 hour down=1.5 hr
r=d/t=6/1.5=4 kph

let's say he takes 2 hours uphill

3*2=6
he goes 6 km
going down he goes 6 kph for one hour
6*1=6
r=d/t=12/3=4 kph