Question 894942
<pre>
{{{321[n] = 232[seven]}}}

{{{3n^2+2n+1 = 2*7^2+3*7+2}}}

{{{3n^2+2n+1 = 98+21+2}}}

{{{3n^2+2n+1 = 121}}}

{{{3n^2+2n = 120}}}

{{{3n^2+2n-120=0}}}

{{{(3n-20)(n-6)=0}}}

3n-20=0;    n-6=0
    n={{{20/3}}}; n=6

n is an integer so n=6

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Checking:

{{{3n^2+2n+1 = 2*7^2+3*7+2}}}

{{{3(6)^2+2(6)+1 =  121}}}

{{{3(36)+12+1 =  121}}}

{{{121=121}}}

Edwin</pre>