Question 894878
{{{y=(x+2)(3-x)(2+x)^2(2x-6)(2x+4)}}}
{{{y=-2(x+2)^4(x-3)^2}}}
Since both terms have even exponents, the value of the function will always be negative except at {{{x=-2}}} and {{{x=3}}} where the value of the function is zero. 
So the max value for the function is zero.

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{{{graph(300,300,-4,4,-1000,1000,-2(x+2)^4(x-3)^2)}}}