Question 10282
with variables multiplied together, you add their powers, so:

{{{x^(3/4) x^(1/3) x^(-1/2)}}} becomes {{{x^(7/12)}}}


{{{(16x^2y^(-1/3))^(3/4)}}}
{{{16^(3/4)(x^2)^(3/4)(y^(-1/3))^(3/4)}}}
{{{(16^(1/4))^3(x^2)^(3/4)(y^(-1/3))^(3/4)}}}
{{{2^3*x^(6/4)*y^(-1/4)}}}
{{{8*x^(3/2)*y^(-1/4)}}}
{{{(8*x^(3/2))/(y^(1/4))}}}


jon.