Question 894587
Looks like you're trying to find the derivative of {{{y=x^x}}}.
{{{y=x^x}}}
Take the natural log of both sides.
{{{ln(y)=xln(x)}}}
Now differentiate,
{{{(dy/dx)/y=x*(1/x)+ln(x)*1}}}
{{{dy/dx=y+y*ln(x)}}}
{{{dy/dx=y(1+ln(x))}}}

{{{dy/dx=x^x*(1+ln(x))}}}