Question 894754
Find the dimensions of a rectangle if the perimeter is 14in and the area is 12cm square
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P = 14 in = 14*2.54 cm
P = 35.56 cm
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P = 2W + 2L = 34.56
L + W = 17.28 --> L = 17.28 - W
L*W = 12
W*(17.28 - W) = 12
W^2 - 17.28W + 12 = 0
*[invoke solve_quadratic_equation 1,-17.28,12]
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W = 1 solution
L = the other