Question 894637
{{{t}}}= hours since 9 AM.
For any time not before 9AM , {{{t>=0}}} ,
train A has traveled {{{150*t}}}{{{km}}} .
For any time not before 11AM , {{{t>=2}}} ,
train B has traveled {{{120*(t-2)}}}{{{km}}} .
If they are to meet at a time such that {{{t>=2}}} ,
{{{150t+120(t-2)=900}}}
{{{150t+120t-120*2=900}}}
{{{150t+120t-240=900}}}
{{{270t=900+240}}}
{{{270t=1140}}}
{{{t=1140/270}}}
{{{t=38/9}}} or {{{t=4&2/9}}}
{{{2/9}}}{{{hour=2*60minutes/9=40/3}}}{{{minutes=13&1/3}}}{{{minutes}}}
{{{1/3}}}{{{minute=60seconds/3=20seconds}}}
So the trains will meet 4 hours, 13 minutes and 20 seconds after 9 AM.
At that time it will be 1:13:20 PM.