Question 894725
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 88 inches, and a standard deviation of 10 inches. What is the likelihood that the mean annual precipitation during 25 randomly picked years will be less than 90.8 inches? 
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z(90.8) = (90.8-88)/[10/sqrt(25)] = 2.8/2 = 1.4
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P(x < 90.8) = P(z < 1.4) = normalcdf(-100,1.4) = 0.9192
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Cheers,
Stan H.
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