Question 894723
12y cubed times z cubed divided by 19 y squared times z to the 4th power
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(12y^3*z^3) / (19y^2*z^4)
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= (12/19)(y^3/y^2)(z^3/z^4)
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= (12/19)(y)(1/z)
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= (12y)/(19z)
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Cheers,
Stan H.
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