Question 894586
Look at the system this way:
3x-2y=6
5x+25y=5


Multiply first one by 5, and second one by 3:
15x-10y=30
15x+75y=15


Subtract an equation from the other:
{{{-85y=15}}}, {{{y=-15/85}}}, {{{highlight(y=-3/17)}}}


Back to original equations,
Multiply first one by 25
Multiply second one by 2:
{{{75x-50y=150}}}
{{{10x+50y=10}}}


Add the corresponding members:
{{{85x=160}}}
{{{x=160/85}}}
{{{highlight(x=32/17)}}}