Question 894111
Find the equation of the hyperbola which satisfies the given condition center (0,0) transverse axis along x-axis, a focus at (8,0) a vertex at (4,0)
***
Given hyperbola has a horizontal transverse axis with center at the origin.
Its standard form of equation: {{{x^2/a^2-y^2/b^2=1}}}
c=8
c^2=64
a=4
a^2=16
c^2=a^2+b^2
b^2=c^2-a^2=64-16=48
equation: {{{x^2/16-y^2/48=1}}}