Question 894114
Find the equation of the hyperbola which satisfies the given condition . Center (0,0), transverse axis along the x-axis, a focus at (5,0),transverse axis = 6
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Given hyperbola has a horizontal transverse axis and center at the origin:
Its standard form of equation: {{{x^2/a^2-y^2/b^2=1}}}
length of transverse axis=6=2a
a=3
a^2=9
c=5
c^2=25
c^2=a^2+b^2
b^2=c^2-a^2=25-9=16
equation: {{{x^2/25-y^2/16=1}}}