Question 894354
{{{abs(((2/5)x-14)/(15x+30))>0}}}
Since the left hand side is the absolute value function, it's value will always be greater than or equal to zero. 
So all {{{x}}} make this true except when the numerator is zero.
{{{(2/5)x-14=0}}}
{{{(2/5)x=14}}}
{{{x=35}}}
In addition, since division by zero is not defined, the value of {{{x}}} when the denominator equals zero is also excluded from the domain.
{{{15x+30=0}}}
{{{15x=-30}}}
{{{x=-2}}}
So the solution region is,
({{{-infinity}}},{{{-2}}})U({{{-2}}},{{{35}}})U({{{35}}},{{{infinity}}})